(expression1 , expression2 [, expressionN... ])

Evaluates expression1, then expression2, and so on. This operator is primarily used with the for loop statement and is often used with the parentheses () operator.

Operands

expression1 : Number - An expression to be evaluated.

expression2 : Number - An expression to be evaluated.

expressionN : Number - Any number of additional expressions to be evaluated.

Returns

Object - The value of expression1, expression2, and so on.

Example

The following example uses the comma (,) operator in a for loop:

for (i = 0, j = 0; i < 3 && j < 3; i++, j+=2) { 
 trace("i = " + i + ", j = " + j); 
} 
// Output: 
// i = 0, j = 0 
// i = 1, j = 2

The following example uses the comma (,) operator without the parentheses () operator and illustrates that the comma operator returns only the value of the first expression without the parentheses () operator:

var v:Number = 0; 
v = 4, 5, 6; 
trace(v); // output: 4 

The following example uses the comma (,) operator with the parentheses () operator and illustrates that the comma operator returns the value of the last expression when used with the parentheses () operator:

var v:Number = 0; 
v = (4, 5, 6); 
trace(v); // output: 6 

The following example uses the comma (,) operator without the parentheses () operator and illustrates that the comma operator sequentially evaluates all of the expressions but returns the value of the first expression. The second expression, z++, is evaluated and z is incremented by one.

var v:Number = 0; 
var z:Number = 0; 
v = v + 4 , z++, v + 6; 
trace(v); // output: 4 
trace(z); // output: 1 

The following example is identical to the previous example except for the addition of the parentheses () operator and illustrates once again that, when used with the parentheses () operator, the comma (,) operator returns the value of the last expression in the series:

var v:Number = 0; 
var z:Number = 0; 
v = (v + 4, z++, v + 6); 
trace(v); // output: 6 
trace(z); // output: 1 

See also

() parentheses operator