How Do I...Compile a Client Against an Interface?

This example illustrates how to build a client that does not reference a server object at compile time. The following code example demonstrates the client code.

using System; using System.Runtime.Remoting; using System.Runtime.Remoting.Channels; using System.Runtime.Remoting.Channels.Tcp; namespace Microsoft.Samples.Remoting.RemotingSamples { public class Client { public static int Main(string [] args) { TcpChannel chan = new TcpChannel(); ChannelServices.RegisterChannel(chan); IHello obj = (IHello)Activator.GetObject(typeof(RemotingSamples.IHello), "tcp://localhost:8085/SayHello"); if (obj == null) System.Console.WriteLine("Could not locate server"); else Console.WriteLine(obj.HelloMethod("Caveman")); return 0; } } } Imports System Imports System.Runtime.Remoting Imports System.Runtime.Remoting.Channels Imports System.Runtime.Remoting.Channels.TCP Namespace Microsoft.Samples.Remoting.RemotingSamples Public Class Client Shared Sub Main Dim chan As TCPChannel chan = New TCPChannel() ChannelServices.RegisterChannel(chan) Dim obj As IHello obj = CType(Activator.GetObject(Type.GetType("RemotingSamples.IHello,share"), "tcp://localhost:8085/SayHello"),IHello) If obj Is Nothing System.Console.WriteLine("Could not locate server") Else Console.WriteLine(obj.HelloMethod("Caveman")) End If End Sub End Class End Namespace #using mscorlib.dll using namespace System; #using using namespace System::Runtime::Remoting; using namespace System::Runtime::Remoting::Channels; using namespace System::Runtime::Remoting::Channels::Tcp; #using "share.dll" using namespace RemotingSamples; void main() { TcpChannel* chan = new TcpChannel(); ChannelServices::RegisterChannel(chan); HelloServer* obj = __try_cast(Activator::GetObject(__typeof(RemotingSamples::IHello), S"tcp://localhost:8085/SayHello")); if (obj) Console::WriteLine(obj->HelloMethod(S"Caveman")); else Console::WriteLine(S"Could not locate server"); }

The client calls GetObject on an endpoint without knowing what the exact object type is. All it knows is that the object implements IHello.